TdNumber Constructor(Double)

Initializes a new instance of TdNumber from the specified Double value.

Syntax

'Declaration
 
Public Function New( _
   ByVal input As Double _
)

'Usage
 
Dim input As Double
 
Dim instance As New TdNumber(input)

public TdNumber( 
   double input
)

public:
TdNumber( 
   double input
)

Exceptions

Exception	Description
System.OverflowException	The input is too large and could not be converted into a TdNumber.

Remarks

The TdNumber instance that results from converting the will represent a Floating decimal that has a scale of 16.

Requirements

Target Platforms: Windows 8.1, Windows 10, Windows Server 2012 R2, Windows Server 2016, Windows Server 2019