Subtract Method (TdIntervalHourToSecond)

A TdIntervalHourToSecond is subtracted from another TdIntervalHourToSecond.

Syntax

Visual Basic
C#
C++/CLI

'Declaration
 
Public Shared Function Subtract( _
   ByVal left As TdIntervalHourToSecond, _
   ByVal right As TdIntervalHourToSecond _
) As TdIntervalHourToSecond

'Usage
 
Dim left As TdIntervalHourToSecond
Dim right As TdIntervalHourToSecond
Dim value As TdIntervalHourToSecond
 
value = TdIntervalHourToSecond.Subtract(left, right)

public static TdIntervalHourToSecond Subtract( 
   TdIntervalHourToSecond left,
   TdIntervalHourToSecond right
)

public:
static TdIntervalHourToSecond Subtract( 
   TdIntervalHourToSecond left,
   TdIntervalHourToSecond right
)

Parameters

left: A TdIntervalHourToSecond to subtract from.
right: A TdIntervalHourToSecond to subtract.

Return Value

A new TdIntervalHourToSecond as the result of subtracting from the .

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalHourToSecond.MaxValue or less than the TdIntervalHourToSecond.MinValue.

Remarks

If either parameter is Null a TdIntervalHourToSecond.Null will be returned.

The returned TdIntervalHourToSecond will contain a precision set to the TdIntervalHourToSecond.MaxPrecision. The scale will always be set to the the scale of the operand containing the greatest scale.

Requirements

Target Platforms: Windows 8.1, Windows 10, Windows Server 2012 R2, Windows Server 2016, Windows Server 2019

Reference

TdIntervalHourToSecond Structure
TdIntervalHourToSecond Members