Subtract(TdIntervalMinute,Int32) Method

The specified number of minutes is subtracted from the TdIntervalMinute.

Syntax

Visual Basic
C#
C++/CLI

'Declaration
 
Public Overloads Shared Function Subtract( _
   ByVal interval As TdIntervalMinute, _
   ByVal minutes As Integer _
) As TdIntervalMinute

'Usage
 
Dim interval As TdIntervalMinute
Dim minutes As Integer
Dim value As TdIntervalMinute
 
value = TdIntervalMinute.Subtract(interval, minutes)

public static TdIntervalMinute Subtract( 
   TdIntervalMinute interval,
   int minutes
)

public:
static TdIntervalMinute Subtract( 
   TdIntervalMinute interval,
   int minutes
)

Parameters

interval: A TdIntervalMinute.
minutes: Number of miinutes to subtract.

Return Value

A new TdIntervalMinute as the result of substracting an Int32 from TdIntervalMinute.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalMinute.MaxValue or less than the TdIntervalMinute.MinValue.

Remarks

If interval is TdIntervalMinute.Null a Null will be returned.

The returned TdIntervalMinute will contain a precision set to the TdIntervalMinute.MaxPrecision.

Requirements

Target Platforms: Windows 8.1, Windows 10, Windows Server 2012 R2, Windows Server 2016, Windows Server 2019

Reference

TdIntervalMinute Structure
TdIntervalMinute Members
Overload List