Multiply(TdIntervalDayToHour,Int32) Method

A TdIntervalDayToHour is multiplied by an integer value.

Syntax

Visual Basic
C#
C++/CLI

'Declaration
 
Public Overloads Shared Function Multiply( _
   ByVal interval As TdIntervalDayToHour, _
   ByVal value As Integer _
) As TdIntervalDayToHour

'Usage
 
Dim interval As TdIntervalDayToHour
Dim value As Integer
Dim value As TdIntervalDayToHour
 
value = TdIntervalDayToHour.Multiply(interval, value)

public static TdIntervalDayToHour Multiply( 
   TdIntervalDayToHour interval,
   int value
)

public:
static TdIntervalDayToHour Multiply( 
   TdIntervalDayToHour interval,
   int value
)

Parameters

interval: A TdIntervalDayToHour.
value: A multiplier.

Return Value

A new TdIntervalDayToHour as the result of multiplying a TdIntervalDayToHour and an integer value.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalDayToHour.MaxValue or less than the TdIntervalDayToHour.MinValue.

Remarks

If interval is TdIntervalDayToHour.Null a Null will be returned.

The returned TdIntervalDayToHour will contain a precision set to the TdIntervalDayToHour.MaxPrecision.

Requirements

Target Platforms: Windows 7, Windows 8, Windows 8.1, Windows 10, Windows Server 2008, Windows Server 2008 R2, Windows Server 2012, Windows Server 2012 R2

Reference

TdIntervalDayToHour Structure
TdIntervalDayToHour Members
Overload List