Subtract Method (TdIntervalDayToHour)

A TdIntervalDayToHour is subtracted from another TdIntervalDayToHour.

Syntax

Visual Basic
C#
C++/CLI

'Declaration
 
Public Shared Function Subtract( _
   ByVal left As TdIntervalDayToHour, _
   ByVal right As TdIntervalDayToHour _
) As TdIntervalDayToHour

'Usage
 
Dim left As TdIntervalDayToHour
Dim right As TdIntervalDayToHour
Dim value As TdIntervalDayToHour
 
value = TdIntervalDayToHour.Subtract(left, right)

public static TdIntervalDayToHour Subtract( 
   TdIntervalDayToHour left,
   TdIntervalDayToHour right
)

public:
static TdIntervalDayToHour Subtract( 
   TdIntervalDayToHour left,
   TdIntervalDayToHour right
)

Parameters

left: A TdIntervalDayToHour to subtract from.
right: A TdIntervalDayToHour to subtract.

Return Value

A new TdIntervalDayToHour as the result of subtracting from the .

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalDayToHour.MaxValue or less than the TdIntervalDayToHour.MinValue.

Remarks

If either parameter is Null a TdIntervalDayToHour.Null will be returned.

The returned TdIntervalDayToHour will contain a precision set to the TdIntervalDayToHour.MaxPrecision.

Requirements

Target Platforms: Windows 7, Windows 8, Windows 8.1, Windows 10, Windows Server 2008, Windows Server 2008 R2, Windows Server 2012, Windows Server 2012 R2

Reference

TdIntervalDayToHour Structure
TdIntervalDayToHour Members