Divide Method (TdIntervalDayToMinute)

A TdIntervalDayToMinute is divided by an integer value.

Syntax

Visual Basic
C#
C++/CLI

'Declaration
 
Public Shared Function Divide( _
   ByVal interval As TdIntervalDayToMinute, _
   ByVal value As Integer _
) As TdIntervalDayToMinute

'Usage
 
Dim interval As TdIntervalDayToMinute
Dim value As Integer
Dim value As TdIntervalDayToMinute
 
value = TdIntervalDayToMinute.Divide(interval, value)

public static TdIntervalDayToMinute Divide( 
   TdIntervalDayToMinute interval,
   int value
)

public:
static TdIntervalDayToMinute Divide( 
   TdIntervalDayToMinute interval,
   int value
)

Parameters

interval: A TdIntervalDayToMinute.
value: A divisor.

Return Value

A new TdIntervalDayToMinute as the result of dividing a TdIntervalDayToMinute and an integer value.

Exceptions

Exception	Description
System.DivideByZeroException	The value divisor cannot be 0.

Remarks

If interval is TdIntervalDayToMinute.Null a Null will be returned.

The returned TdIntervalDayToMinute will contain a precision which matches the precision of the interval parameter.

Requirements

Target Platforms: Windows 7, Windows 8, Windows 8.1, Windows 10, Windows Server 2008, Windows Server 2008 R2, Windows Server 2012, Windows Server 2012 R2

Reference

TdIntervalDayToMinute Structure
TdIntervalDayToMinute Members