Divide Method (TdIntervalSecond)

A TdIntervalSecond is divided by an integer value.

Syntax

Visual Basic
C#
C++/CLI

'Declaration
 
Public Shared Function Divide( _
   ByVal interval As TdIntervalSecond, _
   ByVal value As Integer _
) As TdIntervalSecond

'Usage
 
Dim interval As TdIntervalSecond
Dim value As Integer
Dim value As TdIntervalSecond
 
value = TdIntervalSecond.Divide(interval, value)

public static TdIntervalSecond Divide( 
   TdIntervalSecond interval,
   int value
)

public:
static TdIntervalSecond Divide( 
   TdIntervalSecond interval,
   int value
)

Parameters

interval: A TdIntervalSecond.
value: A divisor.

Return Value

A new TdIntervalSecond as the result of dividing a TdIntervalSecond and an integer value.

Exceptions

Exception	Description
System.DivideByZeroException	The value divisor cannot be 0.

Remarks

If interval is TdIntervalSecond.Null a Null will be returned.

The returned TdIntervalSecond will contain a precision and scale which matches the precision and scale of the interval parameter.

Requirements

Target Platforms: Windows 7, Windows 8, Windows 8.1, Windows 10, Windows Server 2008, Windows Server 2008 R2, Windows Server 2012, Windows Server 2012 R2

Reference

TdIntervalSecond Structure
TdIntervalSecond Members