'Declaration
 
Public Overloads Function Subtract( _
   ByVal interval As TdIntervalDayToSecond _
) As TdDate

'Usage
 
Dim instance As TdDate
Dim interval As TdIntervalDayToSecond
Dim value As TdDate
 
value = instance.Subtract(interval)

public TdDate Subtract( 
   TdIntervalDayToSecond interval
)

public:
TdDate Subtract( 
   TdIntervalDayToSecond interval
) 

Parameters

interval

A TdIntervalDayToSecond that will be subtracted from this instance of TdDate.

Return Value

If the interval or this instance is Null a TdDate.Null will be returned.

The only component of the TdIntervalDayToSecond that will be considered is the day component. When this operation is performed, the TdIntervalDayToSecond.Days component of the TdIntervalDayToSecond is subtracted from this instance of TdDate. For example, if the date is "2007-10-09" and the interval is "5 03:20:30" (5 days, 3 hours, 20 minutes and 30 seconds) the operation will result in "2007-10-04".

Target Platforms: Windows 8.1, Windows 10, Windows Server 2012 R2, Windows Server 2016, Windows Server 2019

Reference

TdDate Structure
TdDate Members
Overload List