Divide Method (TdIntervalDay)

A TdIntervalDay is divided by an integer value.

Syntax

'Declaration
 
Public Shared Function Divide( _
   ByVal interval As TdIntervalDay, _
   ByVal value As Integer _
) As TdIntervalDay

'Usage
 
Dim interval As TdIntervalDay
Dim value As Integer
Dim value As TdIntervalDay
 
value = TdIntervalDay.Divide(interval, value)

public static TdIntervalDay Divide( 
   TdIntervalDay interval,
   int value
)

public:
static TdIntervalDay Divide( 
   TdIntervalDay interval,
   int value
)

A new TdIntervalDay as the result of dividing a TdIntervalDay and an integer value.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalDay.MaxValue or less than the TdIntervalDay.MinValue.
System.DivideByZeroException	The value divisor cannot be 0.

Remarks

If either parameter is Null a TdIntervalDay.Null will be returned.

The returned TdIntervalDay will contain a precision which matches the precision of the interval parameter.

Requirements

Target Platforms: Windows 8.1, Windows 10, Windows Server 2012 R2, Windows Server 2016, Windows Server 2019