Subtract Method (TdIntervalHourToMinute)

A TdIntervalHourToMinute is subtracted from another TdIntervalHourToMinute.

Syntax

Visual Basic
C#
C++/CLI

'Declaration
 
Public Shared Function Subtract( _
   ByVal left As TdIntervalHourToMinute, _
   ByVal right As TdIntervalHourToMinute _
) As TdIntervalHourToMinute

'Usage
 
Dim left As TdIntervalHourToMinute
Dim right As TdIntervalHourToMinute
Dim value As TdIntervalHourToMinute
 
value = TdIntervalHourToMinute.Subtract(left, right)

public static TdIntervalHourToMinute Subtract( 
   TdIntervalHourToMinute left,
   TdIntervalHourToMinute right
)

public:
static TdIntervalHourToMinute Subtract( 
   TdIntervalHourToMinute left,
   TdIntervalHourToMinute right
)

Parameters

left: A TdIntervalHourToMinute to subtract from.
right: A TdIntervalHourToMinute to subtract.

Return Value

A new TdIntervalHourToMinute as the result of subtracting from the .

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalHourToMinute.MaxValue or less than the TdIntervalHourToMinute.MinValue.

Remarks

If either parameter is Null a TdIntervalHourToMinute.Null will be returned.

The returned TdIntervalHourToMinute will contain a precision set to the TdIntervalHourToMinute.MaxPrecision.

The returned TdIntervalHourToMinute will contain a precision adjusted to contain the highest precision from either TdIntervalHourToMinute operands.

Requirements

Target Platforms: Windows 8.1, Windows 10, Windows Server 2012 R2, Windows Server 2016, Windows Server 2019

Reference

TdIntervalHourToMinute Structure
TdIntervalHourToMinute Members