Subtract(TdIntervalYear,Int32) Method

The specified number of years is subtracted from the TdIntervalYear.

Syntax

'Declaration
 
Public Overloads Shared Function Subtract( _
   ByVal interval As TdIntervalYear, _
   ByVal years As Integer _
) As TdIntervalYear

'Usage
 
Dim interval As TdIntervalYear
Dim years As Integer
Dim value As TdIntervalYear
 
value = TdIntervalYear.Subtract(interval, years)

public static TdIntervalYear Subtract( 
   TdIntervalYear interval,
   int years
)

public:
static TdIntervalYear Subtract( 
   TdIntervalYear interval,
   int years
)

A new TdIntervalYear as the result of substracting an Int32 from TdIntervalYear.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalYear.MaxValue or less than the TdIntervalYear.MinValue.

Remarks

If interval is TdIntervalYear.Null a Null will be returned.

The returned TdIntervalYear will contain a precision set to the TdIntervalYear.MaxPrecision.

Requirements

Target Platforms: Windows 8.1, Windows 10, Windows Server 2012 R2, Windows Server 2016, Windows Server 2019