'Declaration
 
Public Overloads Function Subtract( _
   ByVal interval As TdIntervalDayToSecond _
) As TdPeriodTime

'Usage
 
Dim instance As TdPeriodTime
Dim interval As TdIntervalDayToSecond
Dim value As TdPeriodTime
 
value = instance.Subtract(interval)

public TdPeriodTime Subtract( 
   TdIntervalDayToSecond interval
)

public:
TdPeriodTime Subtract( 
   TdIntervalDayToSecond interval
) 

Parameters

interval

The TdIntervalDayToSecond interval will be subtracted from this instance of TdPeriodTime.

Return Value

If this instance of TdPeriodTime or the interval is Null a TdPeriodTime.Null will be returned.

When this operation is performed, the day component of the interval is ignored. Only the hour, minute, and second components are used in this operation. For example, if the period is "05:00:00, 06:30:00" and the interval is "1 02:00:00.00" (1 day, 2 hours) the subtract operation will result in a period of "03:00:00, 04:30:00".

When subtracting a interval from a TdPeriodTime it is possible that the ending bound will roll into the next 24 hours, or the beginning bound will roll into the previous 24 hours. For example, suppose the period is:

   (19:32:32.3404, 22:00:00.3232)

Subtracting the interval of "0 20:00:00" (20 hours) from the period will cause the beginning bound to roll back into the previous 24 hours which results in the invalid period:

    (23:32:32.3404, 02:00:00.3232)

Subtracting the interval of "-0 03:00:00" (-3 hours) from the period will cause the ending bound to roll into the next 24 hours which will result in the invalid period:

    (22:32:32.3404, 01:00:00.3232)

Target Platforms: Windows 8.1, Windows 10, Windows Server 2012 R2, Windows Server 2016, Windows Server 2019

Reference

TdPeriodTime Structure
TdPeriodTime Members
Overload List