Subtract(TdIntervalDay,Int32) Method

The specified number of days is subtracted from the TdIntervalDay.

Syntax

'Declaration
 
Public Overloads Shared Function Subtract( _
   ByVal interval As TdIntervalDay, _
   ByVal days As Integer _
) As TdIntervalDay

'Usage
 
Dim interval As TdIntervalDay
Dim days As Integer
Dim value As TdIntervalDay
 
value = TdIntervalDay.Subtract(interval, days)

public static TdIntervalDay Subtract( 
   TdIntervalDay interval,
   int days
)

public:
static TdIntervalDay Subtract( 
   TdIntervalDay interval,
   int days
)

A new TdIntervalDay as the result of substracting an Int32 from TdIntervalDay.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalDay.MaxValue or less than the TdIntervalDay.MinValue.

Remarks

If interval is TdIntervalDay.Null a Null will be returned.

The returned TdIntervalDay will contain a precision set to the TdIntervalDay.MaxPrecision.

Requirements