Add(Int32,TdIntervalHour) Method

The specified number of hours is added to the TdIntervalHour.

Syntax

'Declaration
 
Public Overloads Shared Function Add( _
   ByVal hours As Integer, _
   ByVal interval As TdIntervalHour _
) As TdIntervalHour

'Usage
 
Dim hours As Integer
Dim interval As TdIntervalHour
Dim value As TdIntervalHour
 
value = TdIntervalHour.Add(hours, interval)

public static TdIntervalHour Add( 
   int hours,
   TdIntervalHour interval
)

public:
static TdIntervalHour Add( 
   int hours,
   TdIntervalHour interval
)

A new TdIntervalHour as the result of adding an Int32 to TdIntervalHour.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalHour.MaxValue or less than the TdIntervalHour.MinValue.

Remarks

If interval is TdIntervalHour.Null a Null will be returned.

The returned TdIntervalHour will contain a precision set to the TdIntervalHour.MaxPrecision.

Requirements