Subtract(TdIntervalMonth,Int32) Method

The specified number of months is subtracted from the TdIntervalMonth.

Syntax

'Declaration
 
Public Overloads Shared Function Subtract( _
   ByVal interval As TdIntervalMonth, _
   ByVal months As Integer _
) As TdIntervalMonth

'Usage
 
Dim interval As TdIntervalMonth
Dim months As Integer
Dim value As TdIntervalMonth
 
value = TdIntervalMonth.Subtract(interval, months)

public static TdIntervalMonth Subtract( 
   TdIntervalMonth interval,
   int months
)

public:
static TdIntervalMonth Subtract( 
   TdIntervalMonth interval,
   int months
)

A new TdIntervalMonth as the result of substracting an Int32 from TdIntervalMonth.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalMonth.MaxValue or less than the TdIntervalMonth.MinValue.

Remarks

If interval is TdIntervalMonth.Null a Null will be returned.

The returned TdIntervalMonth will contain a precision set to the TdIntervalMonth.MaxPrecision.

Requirements