Divide Method (TdIntervalSecond)

A TdIntervalSecond is divided by an integer value.

Syntax

'Declaration
 
Public Shared Function Divide( _
   ByVal interval As TdIntervalSecond, _
   ByVal value As Integer _
) As TdIntervalSecond

'Usage
 
Dim interval As TdIntervalSecond
Dim value As Integer
Dim value As TdIntervalSecond
 
value = TdIntervalSecond.Divide(interval, value)

public static TdIntervalSecond Divide( 
   TdIntervalSecond interval,
   int value
)

public:
static TdIntervalSecond Divide( 
   TdIntervalSecond interval,
   int value
)

A new TdIntervalSecond as the result of dividing a TdIntervalSecond and an integer value.

Exceptions

Exception	Description
System.DivideByZeroException	The value divisor cannot be 0.

Remarks

If interval is TdIntervalSecond.Null a Null will be returned.

The returned TdIntervalSecond will contain a precision and scale which matches the precision and scale of the interval parameter.

Requirements