Multiplication(TdIntervalYearToMonth,Int32) Operator

A TdIntervalYearToMonth is multiplied by an integer value.

Syntax

'Declaration
 
Overloads Public Operator *( _
   ByVal interval As TdIntervalYearToMonth, _
   ByVal value As Integer _
) As TdIntervalYearToMonth

'Usage

public TdIntervalYearToMonth operator *( 
   TdIntervalYearToMonth interval,
   int value
)

public:
TdIntervalYearToMonth operator *( 
   TdIntervalYearToMonth interval,
   int value
)

A new TdIntervalYearToMonth as the result of multiplying a TdIntervalYearToMonth and an integer value.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalYearToMonth.MaxValue or less than the TdIntervalYearToMonth.MinValue.

Remarks

If interval is TdIntervalYearToMonth.Null a Null will be returned.

The returned TdIntervalYearToMonth will contain a precision set to the TdIntervalYearToMonth.MaxPrecision.

Requirements