Divide Method (TdIntervalYear)

A TdIntervalYear is divided by an integer value.

Syntax

'Declaration
 
Public Shared Function Divide( _
   ByVal interval As TdIntervalYear, _
   ByVal value As Integer _
) As TdIntervalYear

'Usage
 
Dim interval As TdIntervalYear
Dim value As Integer
Dim value As TdIntervalYear
 
value = TdIntervalYear.Divide(interval, value)

public static TdIntervalYear Divide( 
   TdIntervalYear interval,
   int value
)

public:
static TdIntervalYear Divide( 
   TdIntervalYear interval,
   int value
)

A new TdIntervalYear as the result of dividing a TdIntervalYear and an integer value.

Exceptions

Exception	Description
System.DivideByZeroException	The value divisor cannot be 0.

Remarks

If interval is TdIntervalYear.Null a Null will be returned.

The returned TdIntervalYear will contain a precision which matches the precision of the interval parameter.

Requirements