'Declaration
 
Public Overloads Function Subtract( _
   ByVal interval As TdIntervalDayToSecond _
) As TdPeriodDate

'Usage
 
Dim instance As TdPeriodDate
Dim interval As TdIntervalDayToSecond
Dim value As TdPeriodDate
 
value = instance.Subtract(interval)

public TdPeriodDate Subtract( 
   TdIntervalDayToSecond interval
)

public:
TdPeriodDate Subtract( 
   TdIntervalDayToSecond interval
) 

Parameters

interval

The number of days from this TdIntervalDayToSecond interval will be subtracted from this instance of TdPeriodDate.

Return Value

If interval or this instance of TdPeriodDate is Null a TdPeriodDate.Null will be returned.

Only the TdIntervalDayToSecond.Days component of the interval will be subtracted from this period.

When this operation is performed, the number of days is subtracted from both the beginning and ending bounds. For example, if the period is ('2007-10-04', '2007-11-01') and the number of days is 2 the subtract operation will result in ('2007-10-02', '2007-10-30').

Reference

TdPeriodDate Structure
TdPeriodDate Members
Overload List