Multiplication(TdIntervalDayToHour,Int32) Operator

A TdIntervalDayToHour is multiplied by an integer value.

Syntax

'Declaration
 
Overloads Public Operator *( _
   ByVal interval As TdIntervalDayToHour, _
   ByVal value As Integer _
) As TdIntervalDayToHour

'Usage

public TdIntervalDayToHour operator *( 
   TdIntervalDayToHour interval,
   int value
)

public:
TdIntervalDayToHour operator *( 
   TdIntervalDayToHour interval,
   int value
)

A new TdIntervalDayToHour as the result of multiplying a TdIntervalDayToHour and an integer value.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalDayToHour.MaxValue or less than the TdIntervalDayToHour.MinValue.

Remarks

If interval is TdIntervalDayToHour.Null a Null will be returned.

The returned TdIntervalDayToHour will contain a precision set to the TdIntervalDayToHour.MaxPrecision.

Requirements