Add(Int32,TdIntervalYear) Method

The specified number of years is added to the TdIntervalYear.

Syntax

'Declaration
 
Public Overloads Shared Function Add( _
   ByVal years As Integer, _
   ByVal interval As TdIntervalYear _
) As TdIntervalYear

'Usage
 
Dim years As Integer
Dim interval As TdIntervalYear
Dim value As TdIntervalYear
 
value = TdIntervalYear.Add(years, interval)

public static TdIntervalYear Add( 
   int years,
   TdIntervalYear interval
)

public:
static TdIntervalYear Add( 
   int years,
   TdIntervalYear interval
)

A new TdIntervalYear as the result of adding an Int32 to TdIntervalYear.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalYear.MaxValue or less than the TdIntervalYear.MinValue.

Remarks

If interval is TdIntervalYear.Null a Null will be returned.

The returned TdIntervalYear will contain a precision set to the TdIntervalYear.MaxPrecision.

Requirements