Multiply(TdIntervalYear,Int32) Method

A TdIntervalYear is multiplied by an integer value.

Syntax

'Declaration
 
Public Overloads Shared Function Multiply( _
   ByVal interval As TdIntervalYear, _
   ByVal value As Integer _
) As TdIntervalYear

'Usage
 
Dim interval As TdIntervalYear
Dim value As Integer
Dim value As TdIntervalYear
 
value = TdIntervalYear.Multiply(interval, value)

public static TdIntervalYear Multiply( 
   TdIntervalYear interval,
   int value
)

public:
static TdIntervalYear Multiply( 
   TdIntervalYear interval,
   int value
)

A new TdIntervalYear as the result of multiplying a TdIntervalYear and an integer value.

Exceptions

Exception	Description
System.OverflowException	The resultant operation returns a value greater than the TdIntervalYear.MaxValue or less than the TdIntervalYear.MinValue.

Remarks

If interval is TdIntervalYear.Null a Null will be returned.

The returned TdIntervalYear will contain a precision set to the TdIntervalYear.MaxPrecision.

Requirements